-64x^2-40x+14=0

Solution for -64x^2-40x+14=0 equation:

-64x^2-40x+14=0

a = -64; b = -40; c = +14;
Δ = b2-4ac
Δ = -402-4·(-64)·14
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-72}{2*-64}=\frac{-32}{-128}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+72}{2*-64}=\frac{112}{-128}
=-7/8
$